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If a light of wavelength 4950 Å is viewe...

If a light of wavelength 4950 `Å` is viewed as a continuous flow of photons, what is the energy of each photon in eV ? (Given `h = 6.6 xx 10^(-34) "Js, c =" 3 xx 10^(8) ms^(-1)`)

Text Solution

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Here `lambda = 4950 Å = 4950 xx 10^(-10) m`
Energy of each photon,
`E = (hc)/(lambda) = (6.6 xx 10^(-34) xx 3 xx 10^(8))/(4950 xx 10^(-10)) = 4 xx 10^(-19)J`
`= (4 xx 10^(-19))/(1.6 xx 10^(-19)) eV`
E = 2.5 eV
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