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If a light of wavelength 4950 Å is viewe...

If a light of wavelength 4950 `Å` is viewed as a continuous flow of photons, what is the energy of each photon in eV ? (Given `h = 6.6 xx 10^(-34) "Js, c =" 3 xx 10^(8) ms^(-1)`)

Text Solution

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Here `lambda = 4950 Å = 4950 xx 10^(-10) m`
Energy of each photon,
`E = (hc)/(lambda) = (6.6 xx 10^(-34) xx 3 xx 10^(8))/(4950 xx 10^(-10)) = 4 xx 10^(-19)J`
`= (4 xx 10^(-19))/(1.6 xx 10^(-19)) eV`
E = 2.5 eV
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Knowledge Check

  • Calculate the energy in joule corresponding to light of wavelength 45 nm. ( h = 6.63 xx 10^(34) J , c = 3 xx 10^(8) ms^(-1))

    A
    `6.67 xx 10^(15) J`
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  • An X-ray tube operates on 30 kV. The minimum wavelength emitted is h = 6.6 xx 10^(-34) Js, c = 3 xx 10^(8) m/s, e = 1.6 xx 10^(-19) C.

    A
    6.6 `Å`
    B
    0.133 `Å`
    C
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    D
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  • A light of wavelength 500 nm is incident on a sensitive plate of photoelectric work function 1.235 eV. The kinetic energy of the photo electrons emitted is be (Take h = 6.6 xx 10^(-34) Js)

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