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Show that one ampere is equivalent to a ...

Show that one ampere is equivalent to a flow of `6.25xx10^(8)` elementary charges per second.

Text Solution

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Here `I=1A, t =1 s, e =1.6xx10^(-19)C`
As `I=(q)/(t)=(n e)/(t)`
Number of electrons, `n=(It)/(e )=(1xx1)/(1.6xx10^(-19))=6.25xx10^(18)`
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