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The radius of the 5^(th) orbit of hydrog...

The radius of the `5^(th)` orbit of hydrogen atom is `13.25 Å`. Calculate the wavelength of the electron in the `5 ^(th)` orbit.

Text Solution

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`2 pi r = n lambda`
` 2 xx 3.14 xx 13.25 Å = 5 xx lambda`
`therefore lambda = 16.64 Å`
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Knowledge Check

  • If the radius of third Bohr orbit in hydrogen atom is r, then de-Broglie wavelength of electron in this orbit is

    A
    `(r )/( 3)`
    B
    3r
    C
    `(2pi r )/( 3)`
    D
    `3 ( 2pi r ) `

  • The ratio between the first three orbits of hydrogen atom is

    A
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    B
    (2:4:6)
    C
    (1:4:9)
    D
    (1:3:5)

  • The ratio between the first three orbits of hydrogen atom is

    A
    `1:2:3`
    B
    `2:4:6`
    C
    `1:4:9`
    D
    `1:3:5`

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