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Suppose an alpha particle accelerated by...

Suppose an alpha particle accelerated by a potential of V volt is allowed to collide with a nucleus whose atomic number is Z, then the distance of closest approach of alpha particle to the nucleus is

A

`14.4(Z)/(V)Å`

B

`14.4(V)/(Z)Å`

C

`1.44(Z)/(V)Å`

D

`1.44(V)/(Z)Å`

Text Solution

Verified by Experts

The correct Answer is:
C
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Knowledge Check

  • A proton and an alpha -particle are accelerated through the same potential difference. The ratio of de-Broglie wavelength of proton to the de-Broglie wavelength of alpha particle will be

    A
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    D
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  • If an alpha - particle collides head on with a nucleus, what is impact parameter?

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    C
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