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The potential difference applied to an X...

The potential difference applied to an X-ray tube is 5kV and the current through it is 3.2 mA. Then the number of electrons striking the target per second is

A

` 2 xx 10^(16)`

B

`5 xx 10^(18)`

C

`1 xx 10^(17)`

D

`4 xx 10^(5)`

Text Solution

Verified by Experts

The correct Answer is:
A
`n = (It)/(e) = (3.2 xx 10^(-3)xx1)/(1.6 xx 10^(-19)) = 2 xx 10^(16)`
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Knowledge Check

  • If the potential difference V applied across a conductor increases to 2V, drift velocity of the electron be

    A
    doubled
    B
    halved
    C
    tripled
    D
    no change

  • The potential difference between the cathode and the target in a coolidge tube is 120 kV. What can be the minimum wavelength (in Å ) of the X-rays emitted by this tube ?

    A
    0.4 `Å`
    B
    0.3 `Å`
    C
    0.2 `Å`
    D
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