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""(92)U^(238) emits 8 alpha particles an...

`""_(92)U^(238)` emits 8 `alpha` particles and 6 `beta` particles. What is the neutron / proton ratio in the product nucleus.?

Text Solution

Verified by Experts

`""_(92)U^(238) overset(-8 alpha) to ""_(76)X^(206)+ 8""_(2)He^(4) (8alpha "decay")`
The result of `alpha` decay
`""_(76)X^(206) overset(-6 beta) to ""_(820)Y^(206)+ 6""_(-6)e^(0)(6 beta "decay")`
Number of proton = 82
Number of neutron 124
The ratio in the product nucleus= `(124)/(82)`
`("neutron")/("proton")= (62)/(41)`
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Knowledge Check

  • A uranium nucleus ""_(92)U^(238) emits an alpha particle and a beta - particle in succession. The atomic number and mass number of the final nucleus will be

    A
    (a) 90233
    B
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    C
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  • The particle which gives mass to protons and neutrons are

    A
    Higgs particle
    B
    Einstein particle
    C
    Nanoparticle
    D
    Bulk particle

  • The particle which gives mass to protons and neutrons are

    A
    Higgs particle
    B
    Einstein particle
    C
    Nanoparticle
    D
    Bulk particle

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