A cricket ball of mass 0.5 kg strikes a bat normally with a velocity of `"30 ms"^(-1)` and rebounds with a velocity of `"20 ms"^(-1)` in the opposite direction, calculate the impulse of the force exerted by the ball on the bat.
Text Solution
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`"Impulse"="Change in momentum"` `= m u-(-m v)` `=m(u+v)=0.5(30+20)=25Ns`
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