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The standard enthalpies of combustion of...

The standard enthalpies of combustion of `C_(6)H_(6)(l), C("graphite") and H_(2)(g)` are respectively `-3270 kJ "mol"^(-1), -394 kJ "mol"^(-1)` and `-286 kJ "mol"^(-1)`. What is the standard enthalpy of formation of `C_(6)H_(6)(l)` in kJ ` "mol"^(-1)`?

A

`-48`

B

`+48`

C

`-480`

D

`+480`

Text Solution

Verified by Experts

The correct Answer is:
B

(i) `C_(6)H_(6)(l) + 15/2O_(2)(g) to 6CO_(2)(g) + 3H_(2)O(l) DeltaH = -3270 kJ "mol"^(-1)`
(ii) `C(gr) + O_(2)(g) to CO_(2)(g) DeltaH = -394 kJ "mol"^(-1)`
(iii) `H_(2)(g) + 1/2O_(2)(g) to H_(2)O(l) DeltaH = -286 kJ "mol"^(-1)`
The required equation is
(iv) `6C(gr) + 3H_(2)(g) to C_(6)H_(6)(l),DeltaH` = ?
Multiply eq.(ii) by 6 and eq(ii) by 3 and adding we get :
(v) `6C(gr) + 15/2O_(2)(g) + 3H_(2)(g) to 6CO_(2)(g) + 3H_(2)O(l), DeltaH = -3222 kJ`
Subtract eq.(i) from eq.(v)
`6C(gr) + 3H_(2)(g) to C_(6)H_(6)(l) DeltaH = + 48 kJ "mol"^(-1)`.
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Knowledge Check

  • The standard enthalpies of combustion of C_(6)H_(6) (l) ,C ( graphite) and H_(2)(g) are respectively -3270 kJ mol^(-1), - 394kJ mol^(-1) and -286 kJmol^(-1) . What is the standard enthalpy of formation of C_(6)H_(6)(l) in kJ mol^(-1) /

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    `- 48`
    B
    `+48`
    C
    `-480`
    D
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  • The standard enthalpies of combustion of C_(6)H_(6(l)),C_(("graphite"))and H_(2(g)) are respectively -3270 kJmol^(-1), -394 kJ mol^(-1) and - 286 kJ mol^(-1) . What is the standard enthalpy of formation of C_(6)H_(6(l)) in kJ mol^(-1)

    A
    `- 48`
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  • If the enthalpies of formation of C_3H_8(g), CO_2(g) and H_2O(l) at standard conditions are -104 kJ mol^-1, -394 kJ mol^-1 and -286 kJ mol^-1 respectively then the standard anthalpy of combustion of 66 g of C_3H_8(g) will be

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