Home
Class 11
CHEMISTRY
Match the term given in Column I withthe...

Match the term given in Column I withthe equation given in Column II
`{:("Column I " , "Column II") , ("(A) Enthalpy of formation", (p) CuSO_(4) (s) + 5 H_(2) O (l) to CuSO_(4) 5H_(2)O), ("(B) Enthalpy of combustion" , (q) CuSO_(4) (s) + nH_(2) O (l) to CuSO_(4) (aq)),("(C) Enthalpy of solution " , (r) C(s) + O_(2) (g) to CO_(2) (g)) , ("(D) Enthalpy of hydration" , (s) CH_(4) + 2 O_(2) to CO_(2) + 2 H_(2)O):}`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of matching the terms in Column I with the equations in Column II, we will analyze each term and its corresponding definition. ### Step-by-Step Solution: 1. **Identify the Terms in Column I**: - (A) Enthalpy of formation - (B) Enthalpy of combustion - (C) Enthalpy of solution - (D) Enthalpy of hydration 2. **Understand Each Term**: - **Enthalpy of Formation**: This refers to the heat change when one mole of a compound is formed from its elements in their standard states. - **Enthalpy of Combustion**: This is the heat change when one mole of a substance is completely burned in oxygen. - **Enthalpy of Solution**: This is the heat change when one mole of solute is dissolved in a solvent. - **Enthalpy of Hydration**: This refers to the heat change when one mole of an ionic compound is dissolved in water. 3. **Analyze Column II Equations**: - (p) \( \text{CuSO}_4 (s) + 5 \text{H}_2O (l) \rightarrow \text{CuSO}_4 \cdot 5\text{H}_2O \) - (q) \( \text{CuSO}_4 (s) + n\text{H}_2O (l) \rightarrow \text{CuSO}_4 (aq) \) - (r) \( \text{C}(s) + \text{O}_2 (g) \rightarrow \text{CO}_2 (g) \) - (s) \( \text{CH}_4 + 2 \text{O}_2 \rightarrow \text{CO}_2 + 2 \text{H}_2O \) 4. **Match Each Term with the Appropriate Equation**: - **(A) Enthalpy of formation**: This matches with (r) because it describes the formation of CO2 from carbon and oxygen, which is a formation reaction. - **(B) Enthalpy of combustion**: This matches with (s) as it describes the complete combustion of methane (CH4) in oxygen, producing CO2 and water. - **(C) Enthalpy of solution**: This matches with (q) because it describes the dissolution of solid CuSO4 into an aqueous solution. - **(D) Enthalpy of hydration**: This matches with (p) as it describes the process of CuSO4 solid combining with water to form a hydrated compound. 5. **Final Matches**: - (A) → (r) - (B) → (s) - (C) → (q) - (D) → (p) ### Final Answer: - (A) Enthalpy of formation → (r) - (B) Enthalpy of combustion → (s) - (C) Enthalpy of solution → (q) - (D) Enthalpy of hydration → (p)
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • THERMODYNAMICS

    MODERN PUBLICATION|Exercise Competition File (Integer Type Questions)|6 Videos
  • THERMODYNAMICS

    MODERN PUBLICATION|Exercise Unit Practice Test|12 Videos
  • THERMODYNAMICS

    MODERN PUBLICATION|Exercise Competition File (Matching Type Questions)|2 Videos
  • STRUCTURE OF ATOM

    MODERN PUBLICATION|Exercise Unit Practice Test|13 Videos

Similar Questions

Explore conceptually related problems

The enthalpy change of the reaction: CuSO_(4)(s) +5H_(2)O(l)rarr CuSO_(4).5H_(2)O(s) is known as the enthalpy of……………

What is % H_(2)O in CuSO_(4).5H_(2)O (Cu = 64, S = 32)

Knowledge Check

  • CuSo_(4) . 5 H_(2)O is a

    A
    solution of a solid in a liquid.
    B
    solution of liquid in a solid
    C
    salt only and cannot be called a solution
    D
    coordination compound of copper with water molecules as the ligands.
  • In solid CuSO_(4).5H_(2)O

    A
    Five molecules of `H_(2)O` are coordinate bonded to `Cu^(2+)`
    B
    `Cu^(2+)` ion is coordinate bonded to four water molecules
    C
    One `H_(2)O` molecule is H-bonded
    D
    It has four type of bonds : Ionic, covalent, coordinate and H-bond
  • In solid CuSO_(4).5H_(2)O

    A
    `Cu^(2+)` ion is coordinate bonded to four water molecules
    B
    One `H_(2)O` molecule is `H-` bonded
    C
    It has four types of bonds, Ionic, covalent, coordinate and H- bond
    D
    Five molecules of `H_(2)O` are coordinate bonded to `Cu^(2+)`
  • Similar Questions

    Explore conceptually related problems

    CuSO_(4).5H_(2)O is blue in colour while CuSO_(4) is colourless, why ?

    CuSO_(4).5H_(2)O is blue in colour while CuSO_(4) is colourless. Why ?

    CuSO_(4)*5H_(2)O belongs to

    Bonds presents in CuSO_(4) .5H_(2)O is

    The valency of copper in CuSO_(4)*5H_(2)O is