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The combustion of benzene (l) gives CO(2...

The combustion of benzene (l) gives `CO_(2)(g)` and `H_(2)O(l)`.Given that heat of combustion of benzene at constant volume is `-3263.9 kJ mol^(-1)` at `25^(@)C`, heat of combustion (in `kJ mol^(-1)`) of benzene at constant pressure will be `(R = 8.314 JK^(-1) mol^(-1)`).

A

4152.6

B

`-452.46`

C

3260

D

`-3267.6`

Text Solution

Verified by Experts

The correct Answer is:
D
`C_(6)H_(6)(l) + (15)/(2) O_(2)(g) to 6CO_(2)(g) + 3H_(2)O(l)`
`Deltan_(g) = 6-15/2 = -3/2`
`DeltaH =DeltaU - Deltan_(g)RT`
`= -3263.9 + (-3/2) xx 8.314 xx 10^(-3) xx 298`
` = -3263.9 - 3.716`
` = - 3267.678`.
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Knowledge Check

  • The combustion of benzene (l) gives CO_(2)(g) and H_(2)O(l) . Given that heat of combustion of benzene at constant volumeis - 3263.9 Kj mol^(-1) at 25^(@)C , heatof combustion ( in kJ mol^(-1)) of benzene at constant pressure will be ( R = 8.314 JK^(-1) mol^(-1))

    A
    4152.6
    B
    `-452.46`
    C
    `3260`
    D
    `-3267.6`

  • The combustion of benzene (1) gives CO_(2)(g) and H_(2)O(1) . Given that heat of combustion of benzene at constant volume is .^(-)3263.9 kJ mol^(-1) " at "25^(@)C , heat of combustion (in kJ mol^(-1) ) of benzene at constant pressure will be (R=8.314 JK^(-1) mol^(-1))

    A
    `- 452.46`
    B
    3260
    C
    `- 3267.6`
    D
    4152.6

  • The combustion of benzene (1) gives CO_(2) (g) and H_(2)O (l). Given that heat of combustion of benzene at constant volume is -3263.9kJ"mol"^(-1) at 25^(@)C , heat of combustion (in kJ"mol^(-1) ) of benzene at constant pressure will be ( R=8.314JK^(-1)"mol"^(-1) )

    A
    4152.6
    B
    `-452.46`
    C
    3260
    D
    `-3267.6`

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