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Arrange the following molecules in the d...

Arrange the following molecules in the decreasing order of oxidation state (+ve to -ve) of nitrogen : `NO_2, NH_3, HN_3, NO_2^(-) , N_2H_4`.

Text Solution

AI Generated Solution

To solve the problem of arranging the molecules in decreasing order of the oxidation state of nitrogen, we will calculate the oxidation state of nitrogen in each compound step by step. ### Step 1: Calculate the oxidation state of nitrogen in NO₂ - The formula for calculating the oxidation state is: \[ x + 2(-2) = 0 \] where \( x \) is the oxidation state of nitrogen and \(-2\) is the oxidation state of oxygen. ...
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Knowledge Check

  • Arrange in the increasing order of oxidation state of nitrogen for following nitrogen oxides N_(2)O, NO_(2), NO, N_(2)O_(3)

    A
    `N_(2)OltNOltNO_(2)ltN_(2)O_(3)`
    B
    `NOltN_(2)OltN_(2)OltN_(2)O_(3)ltNO_(2)`
    C
    `N_(2)OltNOltN_(2)O_(3)ltNO_(2)`
    D
    `NO_(2)ltN_(2)O_(3)ltN_(2)OltNO`

  • The oxidation state of N in HN_3 is

    A
    `+3`
    B
    `-3`
    C
    `-1//3`
    D
    `+1//3`

  • The oxidation state of platinum in Na[PtBrCl(NO_2)(NH_3)] is

    A
    `+2`
    B
    `+4`
    C
    `+6`
    D
    0

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    The hybridisation of atomic orbitals of nitrogen in NO_2^(+), NO_3^(-) and NH_4^(+) are

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