`pK_(b)` of aniline is more than that of methylamine. Why?

Explanation

To understand why the \( pK_b \) of aniline is more than that of methylamine, we need to analyze the basicity of both compounds. Basicity refers to the ability of a compound to accept protons (H⁺ ions), and it is often measured by the base dissociation constant (\( K_b \)).

### Step 1: Understand the Structures of Aniline and Methylamine
- **Aniline (C₆H₅NH₂)**: Aniline consists of a benzene ring attached to an amino group (-NH₂). The structure can be represented as:
\[ \text{C}_6\text{H}_5\text{NH}_2 \]
- **Methylamine (CH₃NH₂)**: Methylamine is a simple amine with a methyl group attached to the amino group. Its structure is:
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