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Standard enthaply of vaporisation Delta(...

Standard enthaply of vaporisation `Delta_(vap)H^(theta)` for water at `100^(@)C` is `40.66 kJ mol^(-1)`. The internal energy of vapourisation of water at `100^(@)C` (in `kJ mol^(-1)`) is :

A

`+ 40.66`

B

`+ 37.56`

C

`- 43.76`

D

`+ 43.76`

Text Solution

Verified by Experts

The correct Answer is:
B

`Delta H = Delta U + Delta n_(g) RT`
`H_(2)O(l) rarr H_(2)O(g)`
`Delta n_(g) = 1, Delta H = 40.66 xx 10^(3) Jmol^(-1)`,
T = 373K
`40660 = Delta U + 1 xx 8.314 xx 373`
`40660 = Delta U + 3101.12`
`Delta U = 40660 - 3101.12`
`= 37.558 Jmol^(-1)`
`= 37. 56 kJmol^(-1)`
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Knowledge Check

  • Standard enthalpy of evaporation Delta_(“vap”)H^@ for water at 100^@C is 40 cdot 66 k J mol^(-1) . The internal energy of vaporization of water at 100^@C (in k J mol^(-1) ) is:

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