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Enthalpy of vaporization of benzene is +...

Enthalpy of vaporization of benzene is `+ 35.3 kJ mol^(-1)` at its boiling point, `80^(@)C`. The entropy change in the transition of the vapour to liquid at its boilling point [in `JK^(-1) mol^(-1)`] is ……….

A

`- 441`

B

`- 100`

C

`+ 441`

D

`+ 100`

Text Solution

Verified by Experts

The correct Answer is:
B
Enthaply change for transition of benzene from water vapour to liquid, `Delta H = - 35.3 kJ mol^(-1)`
Boiling point of benzene, `T = 80^(@)C`
` = (80 + 273) K
= 353 K
`:.` Entropy change, Delta S = (Delta H)/(T) = (-35.3)/(353)`
`= - 0.1 kJ K^(-1) mol^(-1)`
`= - 100 JK^(-1) mol^(-1)`
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Knowledge Check

  • Enthalpy of evaporation of benzene is + 35cdot3 kJ mol^(-1) at its boiling point of 80^@ C. The entropy change in the transition of the vapour to liquid at its boiling points [in Jk^(-1) mol^(-1) ] is ……..

    A
    -441
    B
    -100
    C
    `+441`
    D
    `+100`

  • Enthalpy of vaporization of benzene is +35.3 kJ mol^(-1) at its boiling point 80^(@)C . The entropy chanfe in the transition of the vapour to liquid at boiling point ["in JK"^(-1)"mol"^(-1)] is

    A
    `-441`
    B
    `-100`
    C
    `+441`
    D
    `+100`

  • The enthalpy of vaporization of benzene is +35.3 kJ//mol at its boiling point of 80^(@) C.The entropy change in the transition of vapour to liquid at its boiling point is………..J mol^(-1) K^(-1)

    A
    `-100`
    B
    `+100`
    C
    `+342`
    D
    `-342`

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