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Two liquids X and Y form an ideal soluti...

Two liquids X and Y form an ideal solution. At 300 K, vapour pressure of the solution containing 1 mole of X and 3 mole of Y is 550 mm Hg. At the same temperature, if 1 mole of Y is further added to this solution, vapour pressure of the solution increases by 10 mm Hg. Vapour pressure ( in mm Hg) of X and Y in their pure states will be, respectively :

A

200 and 300

B

300 and 400

C

400 and 600

D

500 and 300

Text Solution

Verified by Experts

The correct Answer is:
C
According to Raoult.s law
`p=p_(X)^(@)x_(X)+p_(Y)^(@)x_(Y)`
Initially, `p=550` mm Hg, `x_(X)=1/4, x_(Y)=3/4`
`550=p_(X)^(@)*1/4+p_(Y)^(@)*3/4` ...(i)
On adding 1 mole of Y
`p=560` mm Hg, `x_(X)=1/5, x_(Y)=4/5`
`560=p_(X)^(@)*1/5+p_(Y)^(@)*4/5` ...(ii)
Solving eq. (i) and (ii), `p_(X)^(@)=400` mm Hg
`p_(Y)^(@)=600` mm Hg.
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Knowledge Check

  • Two liquids X and Y from an ideal solution. At 300 K, vapour pressure of the solution containing 1 mole of X and 3 mol of Y is 550 mm Hg. At the same temperature, if 1 mol of Y is further added to this solution, vapour pressure of the solution increases by 10 mm Hg. Vapour pressure (in mm Hg) of X and Y in their pure states will be respectively

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