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The diagonal of a cube is sqrt12"cm"^3. ...

The diagonal of a cube is `sqrt12``"cm"^3`. Find its volume and surface area.

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To find the volume and surface area of a cube given its diagonal, we can follow these steps: ### Step 1: Understand the relationship between the diagonal and the side length of a cube. The formula for the diagonal \(d\) of a cube in terms of its side length \(s\) is given by: \[ d = s \sqrt{3} \] ### Step 2: Set up the equation using the given diagonal. We are given that the diagonal of the cube is \(\sqrt{12}\) cm. Therefore, we can set up the equation: \[ \sqrt{12} = s \sqrt{3} \] ### Step 3: Solve for the side length \(s\). To isolate \(s\), we can rearrange the equation: \[ s = \frac{\sqrt{12}}{\sqrt{3}} \] Now, simplify \(\sqrt{12}\): \[ \sqrt{12} = \sqrt{4 \times 3} = 2\sqrt{3} \] Substituting this back into the equation gives: \[ s = \frac{2\sqrt{3}}{\sqrt{3}} = 2 \text{ cm} \] ### Step 4: Calculate the volume of the cube. The volume \(V\) of a cube is given by: \[ V = s^3 \] Substituting \(s = 2\) cm: \[ V = 2^3 = 8 \text{ cm}^3 \] ### Step 5: Calculate the surface area of the cube. The surface area \(A\) of a cube is given by: \[ A = 6s^2 \] Substituting \(s = 2\) cm: \[ A = 6 \times (2^2) = 6 \times 4 = 24 \text{ cm}^2 \] ### Final Answers: - Volume of the cube: \(8 \text{ cm}^3\) - Surface area of the cube: \(24 \text{ cm}^2\) ---
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Knowledge Check

  • The diagonal of a cube is 6 sqrt3 cm. Find its volume.

    A
    612 `cm^3`
    B
    216 `cm^3`
    C
    226 `cm^3`
    D
    136 `cm^3`
  • The diagonal of a cube is 12sqrt(3)cm . Its volume and surface area would be

    A
    `1127cm^(3),765cm^(2)`
    B
    `1728cm^(3),864cm^(2)`
    C
    `1540cm^(3),820cm^(2)`
    D
    None of these
  • The diagonal of a cube is 12 sqrt(3) cm. Its volume and surface area would be

    A
    `112 cm^(2) , 765 cm ^(2)`
    B
    `1728 cm ^(2), 864 cm ^(2)`
    C
    `1540 cm ^(3) , 820 cm ^(2)`
    D
    none of these
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