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A wedge of mass M lies on a smooth fixed...

A wedge of mass M lies on a smooth fixed wedge of inclination `theta`. A particle of mass m lies on the wedge of mass M in the figure. All surfaces are frictionless and the distance of the block from the fixed wedge is `l`. Find.

(a) Normal reaction between m and M
(b) the time after which the particle will hit the fixed plane.

Text Solution

Verified by Experts

In the reference frame attached to wedge of mass M the particle of mass m can only move horizontally.

FBD of wedge of mass M with respect to FBD of particle w.r.t. wedge of mass M ground
Applying Newton.s `2^(nd)` law of the particle
`N+ma_(wq)sin theta=mg " " ...(i)`
`ma_(wq)cos theta=ma_(mM)" "...(ii)`
Applying Newton.s `2^(nd)` law for wedge of mass M
`N sin theta+mg sin theta=Ma_(wq)" " ...(iii)`
Solving (i), (ii) and (iii) we get
`a_(wq)=((M+m)g sin theta)/(M+m sin^(2)theta)`
`N=(Mmgcos^(2)theta)/((M+m sin^(2)theta))`
`a_(mM)=((M+m)g sin theta cos theta)/(M+m sin^(2)theta)`
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Knowledge Check

  • A block of mass m is placed on a smooth wedge of inclination theta & mass M. The whole system is slip on the wedge. Then the normal reaction on the wedge acting from the ground :

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    `a=(F(1+cos theta)+mg sin theta cos theta)/(M+m sin^(2)theta)`
    C
    `a=(F(1-cos theta)-mg sin theta cos theta)/(M+m sin^(2)theta)`
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    `a=(F(1+cos theta)-mg sin theta cos theta)/(M-m sin^(2)theta)`
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