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Two circular coils X and Y, having equal...

Two circular coils X and Y, having equal number of turns and carrying currents in the same sense, subtend same solid angle at point O. If the smaller coil X is midway between O and Y and if we represent the magnetic induction due to bigger coil Y at O as `B_y` and the due to smaller coil X at O as `B_x`,then find the ratio `B_x//B_y`.

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Knowledge Check

  • Two circular coils A and B with their centres lying on the same axis have differents in the same sence. The coil B lies exacity midway between coil A and the point P. The magnetic field at point P due to coils A and B is B_(1) and B_(2) respectively.

    A
    `B_(1) gtB_(2)`
    B
    `B_(1) ltB_(2)`
    C
    `(B_(1))/(B_(2))=2`
    D
    `(B_(1))/(B_(2))=(1)/(2)`

  • A and B are two conductors carrying a current I in the same direction, X and y are two electron beams moving in the same direction. Then there will be

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    attraction between A and B, repulsion between x and y
    B
    repulsion between A and B, attraction between x and y
    C
    attraction between 4 and B and r and y
    D
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  • A circular coil of radius 'r' having 'n' turns carries a current 'I' . The magnetic induction at the center of the coil is 'B' . Now the coil is unwound and rewound with half the original radius. If the magnetic induction at the center of the coil is to be the same, the current that should be passed through the coil is

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