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A dip needle lies initially in the magne...

A dip needle lies initially in the magnetic merdian when it shows an angle of dip `theta` at a place. The dip circle is rotated through an angle x in the horizontal plane and then it shows an angle of dip `theta^(')`. Then `tantheta^(')/tantheta` is

A

`1// cos alpha`

B

`1 // sin alpha`

C

`cos alpha`

D

`sin alpha`

Text Solution

Verified by Experts

The correct Answer is:
A
` tan theta = (By)/(B_H)`
`tan theta = (BV)/(B_H cos alpha)`
`therefore (tan theta)/(tan theta) = 1/ (cos alpha)`
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Knowledge Check

  • Angle of dip is zero at

    A
    poles
    B
    between poles of equator.
    C
    equator
    D
    none of these

  • The angle of dip is the angle

    A
    Between the vertical component of earth's magnetic field and magnetc meridian
    B
    Between the vertical component of earth's magnetic field and geographical meridian
    C
    Between the earth's magnetic field direction and horizontal direction
    D
    Between the magnetic meridian and the geographical meridian

  • Angle of dip is 90^(@) at

    A
    Poles
    B
    Equator
    C
    Both (a) and (b)
    D
    None of these