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A magnetised wire of moment M is bent in...

A magnetised wire of moment M is bent into an arc of a circle subtending an angle of 60^(@) at the centre. The new magnetic moment is

A

`3M//pi `

B

`M//pi`

C

`2M//pi`

D

`3sqrt(3)M// pi`

Text Solution

Verified by Experts

The correct Answer is:
A
New magnetic moment .
`M = M xx (2 sin (theta //2))/(theta) = M xx (2xx (1//2))/(pi//3) = (3M)/(pi)`
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Knowledge Check

  • A magnetised wire is bent into an arc of a circle subtending an angle 60^(@) at its centre. Then its magnetic moment is X. If the same wire is bent into an are of a circle subtending an angle 90^(@) at its centre then its magnetic moment will be

    A
    `(xsqrt2)/3`
    B
    `x/3`
    C
    `((2sqrt2)x)/3`
    D
    `(3x)/(2sqrt2)`

  • A magnetised wire is bent into an arc of a circle subtending an angle 90^(0) at its centre then its manetic moment will be

    A
    `(xsqrt2)/(3)`
    B
    `(x)/(3)`
    C
    `((2sqrt2)x)/(3)`
    D
    `(3x)/(2sqrt2)`

  • If the piece of wire 25 cm long is bent into an arc of a circle subtending an angle of 75^(@) at the centre , then the radius of the circle ( in cm ) is :

    A
    `(pi)/(120)`
    B
    `(60)/(pi)`
    C
    `60 pi `
    D
    none of these