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If A ,\ B ,\ C ,\ D be the angles of a c...

If `A ,\ B ,\ C ,\ D` be the angles of a cyclic quadrilateral, taken in order, prove that: `cos(180^0-A)+cos(180^0+B)+cos(180^0+C)-sin(90^0+D)=0`

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Knowledge Check

  • If A,B,C,D are the angles of a cyclic quadrilateral and cos A+cos B= K(cos C + cos D), then the value of K is

    A
    1
    B
    `-1`
    C
    2
    D
    `-2`

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