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MODERN PUBLICATION-MATHEMATICAL INDUCTION-Exercise
- 4^(n)-1 is divisible by 3, for each natural number n.
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- Using the principle of mathematical induction, prove that (2^(3n)-1...
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- 3^(2n)-1 is divisible by 8, for all natural numbers n.
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- n^(3)-n is divisible by 6, for each natural numbers n ge2
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- n(n^(2)+5) is divisible by 6, for each natural number n.
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- n^(2)lt2^(n), for all natural number nle5.
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- For all n in N, 1 + 1/(sqrt(2))+1/(sqrt(3))+1/(sqrt(4))++1/(sqrt(n))
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- 1+5+9+...+(4n-3)=n(2n-1) for all natural numbers n
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- A sequence b(0),b(1),b(2), . . . is defined by letting b(0)=5 and b(k)...
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- Using induction, prove that cos theta · cos 2theta · cos 2^2 theta. ....
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