Same amount of electric current is passed through solutions of `AgNO_(3)` and HCl. If 1.08g of silver is obtained in the first case, the amount of hydrogen liberated at S.T.P. in the second case is

Options

A. `224cm^(3)`
B. `1.008g`
C. `112cm^(3)`
D. `22400cm^(3)`

Answer

C

Explanation

According to Faraday.s second law
`("Mass of Ag")/("Mass of H")=("Equivalent mass of silver")/("Equivalent mass of hydrogen")`
or `(1.08)/("Mass of H")=(108)/(1)` or mass, `H=0.01g`
`because2.00` gm of `H_(2)` occupies 22400 ml at STP
`therefore 0.01`gm of `H_(2)` will occupy`=(22400xx0.01)/(2)`
`=112cm^(3)`.