Home
Class 12
CHEMISTRY
15 moles of H(2) and 5.2 moles of I(2) a...

15 moles of `H_(2)` and `5.2` moles of `I_(2)` are mixed and allowed to attain equilibrium at `500^(@)C`. At equilibrium, the concentration of HI is found to be 10 moles. The equilibrium constant for the formation of HI is

A

50

B

15

C

100

D

25

Text Solution

Verified by Experts

The correct Answer is:
a

`underset(15-5)underset(15)(H_(2))+underset(5.2-5)underset(5.2)(I_(2))hArrunderset(10)underset(0)(2HI)`
`K_(c)=[HI]^(2)/[[I_(2)])=(10xx10)/(10xx0.2)=50`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • KARNATAKA CET 2003

    KCET PREVIOUS YEAR PAPERS|Exercise CHEMISTRY|60 Videos
  • KARNATAKA CET 2006

    KCET PREVIOUS YEAR PAPERS|Exercise CHEMISTRY|60 Videos