15 moles of `H_(2)` and `5.2` moles of `I_(2)` are mixed and allowed to attain equilibrium at `500^(@)C`. At equilibrium, the concentration of HI is found to be 10 moles. The equilibrium constant for the formation of HI is

Options

A. 50
B. 15
C. 100
D. 25

Answer

a

Explanation

`underset(15-5)underset(15)(H_(2))+underset(5.2-5)underset(5.2)(I_(2))hArrunderset(10)underset(0)(2HI)`
`K_(c)=[HI]^(2)/[[I_(2)])=(10xx10)/(10xx0.2)=50`