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The product of the roots of the equation...

The product of the roots of the equation `x|x|-5x-6=0` is equal to

A

36

B

`-36`

C

`-18`

D

6

Text Solution

AI Generated Solution

The correct Answer is:
To find the product of the roots of the equation \( x|x| - 5x - 6 = 0 \), we will analyze the equation by considering two cases based on the definition of the absolute value function. ### Step 1: Break down the equation based on the sign of \( x \) The absolute value function \( |x| \) behaves differently based on whether \( x \) is positive or negative. Therefore, we will consider two cases: - **Case 1**: \( x \geq 0 \) - **Case 2**: \( x < 0 \) ### Step 2: Solve Case 1: \( x \geq 0 \) In this case, \( |x| = x \). Thus, the equation becomes: \[ x^2 - 5x - 6 = 0 \] Now, we will use the quadratic formula to find the roots: \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \] Here, \( a = 1, b = -5, c = -6 \): \[ x = \frac{5 \pm \sqrt{(-5)^2 - 4 \cdot 1 \cdot (-6)}}{2 \cdot 1} \] Calculating the discriminant: \[ x = \frac{5 \pm \sqrt{25 + 24}}{2} = \frac{5 \pm \sqrt{49}}{2} = \frac{5 \pm 7}{2} \] This gives us two roots: \[ x_1 = \frac{12}{2} = 6 \quad \text{and} \quad x_2 = \frac{-2}{2} = -1 \] Since we are in the case where \( x \geq 0 \), we only take \( x_1 = 6 \). ### Step 3: Solve Case 2: \( x < 0 \) In this case, \( |x| = -x \). Thus, the equation becomes: \[ -x^2 - 5x - 6 = 0 \] Multiplying through by -1 gives: \[ x^2 + 5x + 6 = 0 \] Again, we will use the quadratic formula: \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \] Here, \( a = 1, b = 5, c = 6 \): \[ x = \frac{-5 \pm \sqrt{5^2 - 4 \cdot 1 \cdot 6}}{2 \cdot 1} \] Calculating the discriminant: \[ x = \frac{-5 \pm \sqrt{25 - 24}}{2} = \frac{-5 \pm \sqrt{1}}{2} = \frac{-5 \pm 1}{2} \] This gives us two roots: \[ x_3 = \frac{-4}{2} = -2 \quad \text{and} \quad x_4 = \frac{-6}{2} = -3 \] Both roots \( x_3 = -2 \) and \( x_4 = -3 \) are valid since we are in the case where \( x < 0 \). ### Step 4: Collect all roots From both cases, we have the roots: - From Case 1: \( 6 \) - From Case 2: \( -2, -3 \) ### Step 5: Calculate the product of the roots The product of the roots is: \[ P = 6 \times (-2) \times (-3) \] Calculating this: \[ P = 6 \times 2 \times 3 = 36 \] ### Final Answer The product of the roots of the equation \( x|x| - 5x - 6 = 0 \) is equal to \( 36 \). ---
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DISHA PUBLICATION-COMPLEX NUMBERS AND QUADRATIC EQUATIONS -Exercise-1: Concept Builder (Topic -3)
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  5. If alpha, beta are real and alpha^(2), beta^(2) are the roots of the e...

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  13. If one root of the equation ax^2+bx+c=0 is the square of the other , t...

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  14. The ration of roots of the equations ax^(2) + bx + c =0 and px^(2) + q...

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  15. If x^(2)+y^(2)=25, xy=12 then x=

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  16. If a ,b ,c(a b c^2)x^2+3a^2c x+b^2c x-6a^2-a b+2b^2=0 ares rational.

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  17. Find the roots of the following equations. x^(2)-7x+12=0

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