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A point object is placed at the centre o...

A point object is placed at the centre of a glass sphere of radius 6cm and refractive index 1.5. The distance of virtual image from the surface is

A

`2 cm

B

4 cm

C

6 cm

D

12 cm

Text Solution

Verified by Experts

The correct Answer is:
C

`(mu_(2))/(v)-(mu_(1))/(v)=(mu_(2)-mu_(1))/(R )`
`or(1)/(v)-(1.5)/(-R)=(1-1.5)/(-R)`
`therefore" "v=-R=-6cm`
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Knowledge Check

  • A point object is placed at the center of a glass sphere of radius 6cm and refractive index 1.5. The distance of virtual image from the surface is

    A
    6cm
    B
    4cm
    C
    12cm
    D
    9cm
  • A point object is placed at the centre of a glass sphere of radius 6 cm and refractive index 1.5. The distance of the virtual image from the surface of the glass is

    A
    2 cm
    B
    4 cm
    C
    6 cm
    D
    12 cm
  • Figure shows a point object placed in front of a transparent sphere of radius 20 cm and refractive index 1.5. The sphere forms an image due to refraction at surface I followed by refraction at surface II. The sphere is kept in air and the object is located at distance x from P_(1) . It is found that for x gt x_(1) , the image formed due to refraction at surface I is real, the final image formed by the sphere is also real and forms to the right of P_(2) . For x_(2) lt x lt x_(1) , the image formed by surface I is virtual while the final image formed by the sphere is real and forms to the right of P_(2) . However for x lt x_(2) , the image formed by surface I and also the final image formed by the sphere are virtual. It is also found that the final image is virtual if the distance of image formed by surface I from P_(2) is less than y. The object is now moved away from the sphere so that x becomes large and say, x to oo . In the given sphere is replaced by another one of the same radius but of refractive index 2.5, the final image is formed at distance y_(2) from P_(2) . For the object placed at x to oo , the given sphere of refractive index 1.5 forms an image at distance y_(1) from P_(2) .

    A
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    B
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    C
    this image is real and `y_(1)=20 cm " right of " P_(2)`
    D
    this image is virtual and `y_(1)=12 cm " left of " P_(2)`
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