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Rate constant k = 1.2 xx 10^(3) mol^(-1)...

Rate constant `k = 1.2 xx 10^(3) mol^(-1) L s^(-1)` and `E_(a) = 2.0 xx 10^(2) kJ mol^(-1)`. When `T rarr oo`:

A

`A=2.0 xx 10^(2) kJ mol^(-1)`

B

`A=1.2 xx 10^(3) mol^(-1)L^(-1)s^(-1)`

C

`A=1.2 xx 10^(3) mol L^(-1)s^(-1)`

D

`A=2.4 xx 10^(3) kJ mol^(-1) s^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B
`k=Ae^(-E // RT)`
If `T to infty`, k = A
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Knowledge Check

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