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Rate constant k = 1.2 xx 10^(3) mol^(-1)...

Rate constant `k = 1.2 xx 10^(3) mol^(-1) L s^(-1)` and `E_(a) = 2.0 xx 10^(2) kJ mol^(-1)`. When `T rarr oo`:

A

`A=2.0 xx 10^(2) kJ mol^(-1)`

B

`A=1.2 xx 10^(3) mol^(-1)L^(-1)s^(-1)`

C

`A=1.2 xx 10^(3) mol L^(-1)s^(-1)`

D

`A=2.4 xx 10^(3) kJ mol^(-1) s^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B
`k=Ae^(-E // RT)`
If `T to infty`, k = A
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Knowledge Check

  • For a reaction 2N_2O_5 rarr 4NO_2 + O_2 , rate and rate constant are 1.02 xx 10^(-4)" mol " L^(-1)s^(-1) and 3.4 xx 10^(-5)s^(-1) The concentration of N_2O_5 at that time will be

    A
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    B
    3 mol `L^(-1)`
    C
    `1.02xx10^(-4) " "mol" "L^(-1)`
    D
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    A
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    B
    `2.6 "kcal mol"^(-1)`
    C
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    D
    `260 "kcal mol"^(-1)`

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    B
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    C
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    D
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