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Cyclopropane rearranges to form propane ...

Cyclopropane rearranges to form propane :
`DeltararrCH_(3)-CH=CH_(2)`
This follows first order kinetics. The rate constant is `2.174xx10^(-3) "sec"^(-1)` . The initial concentration of cyclopropane is `0.29 M` . What will be the concentration of cyclopropane after 100 sec

A

0.035M

B

0.22 M

C

0.145 M

D

0.0018M

Text Solution

Verified by Experts

The correct Answer is:
B
`k=(2.303)/(t)log""(a)/((a-x))`
(a-x) is the concentration left after 100 sec.
`2.7 xx 10^(-3)=(2.303)/(100)log ""(0.29)/((a-x))`
`implies (0.27)/(2.303)=log""(0.29)/((a-x))implies 0.117=log""(0.29)/((a-x))`
`implies` (a - x)=0.22 M.
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Knowledge Check

  • Cyclopropane rearranges to form propene Delta to CH_(3) - CH = CH_(2) This follows first order kinetics . The rate constant is 2.714 xx 10^(-3) sec^(-1) . The initial concentration of cyclopropane is 0.29 M . What will be the concentration of cyclopropane after 100 sec .

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    C
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    D
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  • Cyclopropane rearranges to form propene This follows first order kinetics. The rate constant is 2.714 xx 10^(-3)" sec"^(-1) . The initial concentration of cyclopropane is 0.29 M. What will be the concentration of cyclopropane after 100 sec?

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