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0.02 mole of [Co(NH(3))(5)Br]Cl(2) and 0...

0.02 mole of `[Co(NH_(3))_(5)Br]Cl_(2) and 0.02" mole of "[Co(NH_(3))_(5)Cl]SO_(4)` are present in 200 cc of a solution X. The number of moles of the precipitates Y and Z that are formed when the solution X is treated with excess silver nitrate and excess barium chloride are respectively

Text Solution

Verified by Experts

The correct Answer is:
0.04
When excess of `AgNO_(3)` and `BaCl_(2)` are added to solution X.
`[Co(NH_(3))_(5) Br]Cl_(2) + 2AgNo_(3) to underset(1 "mol")[Co(NH_(3))_(5) Br](NO_(3))_(2) + underset(2 mol, 0.02 xx 2 = 0.04 mol)(2AgCl(ppt.Y)`
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Give evidence that [Co(NH_(3))_(5)Cl]SO_(4) and [Co(NH_(3))_(5)SO_(4)]Cl are ionisation isomers.

Give evidence that [Co(NH_(3))_(5)Cl]SO_(4) and [Co(NH_(3))_(5)SO_(4)]Cl are ionisation isomers.

Knowledge Check

  • The compounds [Co(SO_(4))(NH_(3))_(5)]Br and [Co(SO_(4))(NH_(3))_(5)]Cl

    A
    Linkage isomerism
    B
    Ionisation isomerism
    C
    coordinatio isomerism
    D
    no isomerism

  • The compounds [Co(SO_(4))(NH_(3))_(5)]Br and [Co(SO_(4))(NH_(3)) _(5)]Cl represent

    A
    linkage isomerism.
    B
    ionisation isomerism.
    C
    coordination isomerism.
    D
    No isomerism.

  • When two moles of [Co(NH_3)_5Cl]Cl_2 is treated with excess silver nitrate solution, the number of moles of silver chloride formed is

    A
    3
    B
    6
    C
    4
    D
    2

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