(i) `sinx=(sqrt(3))/(2)`
(ii) `cosx=1`
(iii) `secx=sqrt(2)`

Answer

Let's solve the given trigonometric equations step by step.

### (i) Solve `sin x = (sqrt(3))/(2)`

1. **Identify the angle**: We know that `sin(π/3) = √3/2`. Therefore, we can say:
\[ x = \frac{\pi}{3} \]

2. **General solution for sine**: The general solution for `sin x = sin α` is given by:
\[ x = n\pi + (-1)^n \alpha \]
where `α = π/3`.

3. **Substituting α into the formula**:
\[ x = n\pi + (-1)^n \frac{\pi}{3} \]

4. **Final general solution**:
\[ x = n\pi + (-1)^n \frac{\pi}{3}, \quad n \in \mathbb{Z} \]