Home
Class 9
MATHS
In the figure 'O' is the centre of the c...

In the figure 'O' is the centre of the circle
`angle AOB = 100^@ ` find `angle ADB`

Text Solution

Verified by Experts

The correct Answer is:
`130^@`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • CIRCLES

    NCERT BANGLISH|Exercise EXERCISE 12.5|5 Videos

  • CIRCLES

    NCERT BANGLISH|Exercise EXERCISE 12.3|7 Videos

  • AREAS

    NCERT BANGLISH|Exercise EXERCISE 11.3|9 Videos

  • CO-ORDINATE GEOMETRY

    NCERT BANGLISH|Exercise Try These|2 Videos

Similar Questions

Explore conceptually related problems

In the figure , O is the centre of the circle and angle POR = 120^@ . Find angle PQR " and " angle PSR

In the adjacent figure O is the centre of the circle. If angle OAB=30^(@), angle ABC=120^(@), angle BCO=y^(@) and angle COA=x^(@) , then the find value sof x and y.

Knowledge Check

  • In the adjoining figure, O is the centre of the circle. If angle AEB=110^(@), angle CBE=30^(@) , then the value of angle ADB is

    A
    `70^(@)`
    B
    `60^(@)`
    C
    `80^(@)`
    D
    `90^(@)`

  • In the adjoining figure,O is centre of the circle , If angle ACB= 30^(@), angle ABC=60^(@), angle DAB= 35^(@) and angle DBC=x^(@) , then the value of x is

    A
    35
    B
    40
    C
    65
    D
    55

  • In the adjoining firgure, O is the centre of the circle, if angle BAD=65^(@), angle BDC=45^(@) then the value of angle CBD is

    A
    `65^(@)`
    B
    `45^(@)`
    C
    `40^(@)`
    D
    `20^(@)`

    • Similar Questions

    Explore conceptually related problems

    In the figure angle BAD = 40^@ then find angle BCD

    In the adjoining figure, O is the centre of the circle and AB= AC , if angleABC=32^(@) , then find the value angle BDC

    In the figure, ‘O’ is the centre of the circle. OM = 3cm and AB = 8cm. Find the radius of the circle

    In the given figure ‘O’ is the centre of the circle and AB, CD are equal chords. If angleAOB = 70^@ . Find the angles of the Delta OCD

    In the figure , ABCD is a cyclic quadrilateral O is the centre of the circle. If angleOAD = 30^@ and angleOCD = 20^@ ,then find angleABC

    Home
    Profile