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The correct order of increasing boiling ...

The correct order of increasing boiling of the following aqueous solutions
0.0001 M NaCl (I), 0.0001 M Urea (II), 0.001 M `MgCl_(2)` (III), 0.01 M NaCl (IV) is

A

`I lt II lt III lt IV `

B

`IV lt III lt II lt I`

C

`II lt I lt III lt IV `

D

`III lt II lt IV lt I `

Text Solution

AI Generated Solution

The correct Answer is:
To determine the correct order of increasing boiling points of the given aqueous solutions, we need to use the formula for boiling point elevation, which is given by: \[ \Delta T_b = i \cdot K_b \cdot m \] Where: - \(\Delta T_b\) is the elevation in boiling point. - \(i\) is the van 't Hoff factor (the number of particles the solute breaks into). - \(K_b\) is the ebullioscopic constant (which is constant for a given solvent, in this case, water). - \(m\) is the molality of the solution. Since \(K_b\) is constant for all solutions in this case, we can focus on the product \(i \cdot m\) to compare the boiling points. ### Step 1: Calculate \(i\) for each solute 1. **0.0001 M NaCl (I)**: - NaCl dissociates into 2 ions (Na\(^+\) and Cl\(^-\)). - \(i = 2\) 2. **0.0001 M Urea (II)**: - Urea does not dissociate in solution. - \(i = 1\) 3. **0.001 M MgCl\(_2\) (III)**: - MgCl\(_2\) dissociates into 3 ions (Mg\(^{2+}\) and 2 Cl\(^-\)). - \(i = 3\) 4. **0.01 M NaCl (IV)**: - NaCl dissociates into 2 ions (Na\(^+\) and Cl\(^-\)). - \(i = 2\) ### Step 2: Calculate \(i \cdot m\) for each solution 1. **0.0001 M NaCl (I)**: - \(i \cdot m = 2 \cdot 0.0001 = 0.0002\) 2. **0.0001 M Urea (II)**: - \(i \cdot m = 1 \cdot 0.0001 = 0.0001\) 3. **0.001 M MgCl\(_2\) (III)**: - \(i \cdot m = 3 \cdot 0.001 = 0.003\) 4. **0.01 M NaCl (IV)**: - \(i \cdot m = 2 \cdot 0.01 = 0.02\) ### Step 3: Compare the values of \(i \cdot m\) Now we can arrange the solutions in order of increasing boiling point based on the calculated \(i \cdot m\) values: - **0.0001 M Urea (II)**: \(0.0001\) - **0.0001 M NaCl (I)**: \(0.0002\) - **0.01 M NaCl (IV)**: \(0.02\) - **0.001 M MgCl\(_2\) (III)**: \(0.003\) ### Step 4: Final order of increasing boiling point From the values calculated, we can conclude that the order of increasing boiling point is: **0.0001 M Urea (II) < 0.0001 M NaCl (I) < 0.001 M MgCl\(_2\) (III) < 0.01 M NaCl (IV)** ### Final Answer: The correct order of increasing boiling points is: **(II) < (I) < (III) < (IV)**

To determine the correct order of increasing boiling points of the given aqueous solutions, we need to use the formula for boiling point elevation, which is given by: \[ \Delta T_b = i \cdot K_b \cdot m \] Where: - \(\Delta T_b\) is the elevation in boiling point. ...
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Knowledge Check

  • The correct order of increasing boiling points of the following aqueous solutions 0.0001MNaCl(I)," 0.0001M Urea (II) ", 0.001MMgCl_(2)(III)," 0.01MNaCl(IV) is"

    A
    `I lt II lt III lt IV`
    B
    `IV lt III lt II lt I`
    C
    `II lt I lt III lt IV`
    D
    `III lt II lt IV lt I`
  • The correct order of osmotic pressure of 0.01M aqueous solution of the following is

    A
    `"Sucrose" gt CH_3COOH gt KCl`
    B
    `CH_3 COOH gt "Sucrose" gt KCl`
    C
    `"Sucrose " gt KCl gt CH_3COOH`
    D
    `KCl gt CH_3COOH gt" Sucrose"`
  • Properties such as boiling point, freezing point, and vapour pressure of a pure solvent change when solute molecules are added to get homogenous solution. These are called colligative properties. Anwer the following questions: i. 0.001 m NaCl ii.0.001 m urea iii. 0.001 m MgCl_(2) iv. 0.001 m CH_(3)COOH Increasing order of boiling points

    A
    `(ii) lt (iv) lt (i) lt (iii)`
    B
    `(iv) lt (i) lt (ii) lt (iii)`
    C
    `(iii) lt (ii) lt (i) lt (iiv)`
    D
    `(i) lt (ii) lt (iii) lt (iv)`
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