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After emission of one alpha particle fol...

After emission of one `alpha` particle followed by one `beta`-particle from `""_(92)^(238)X`, the number of neutrons in the atom will be

A

142

B

146

C

144

D

143

Text Solution

Verified by Experts

The correct Answer is:
D
`._(92)X^(238) overset(-alpha)rarr ._(90)Y^(234)overset(-beta)rarr ._(91)Z^(234)`
no. of neutrons `= 234 - 91 = 143`
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