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U^(235) + n^(1)rarr fission product + ne...

`U^(235) + n^(1)rarr` fission product + neutron + 3.2`xx 10^(-11)j`. The energy released , when 1g of `u^(235)` finally undergoes fission , is

A

`12.75 xx 10^(8) kJ`

B

`18.60 xx 10^(9) kJ`

C

`8.21 xx 10^(7) kJ`

D

`6.55 xx 10^(6) kJ`

Text Solution

Verified by Experts

The correct Answer is:
C
`1g U-235 = (6.023 xx 10^(23))/(235)` atoms
`:.` Energy released `= 3.2 xx 10^(-11) xx (6.023 xx 10^(23))/(235) J`
`= 8.21 xx 10^(1) J = 8.2 xx 10^(7) kJ`
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