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Silver chloride dissolves in excess ammo...

Silver chloride dissolves in excess ammonia due to the formation of a soluble compplex whose formula is

A

`[Ag(NH_(4))_(2)OH`

B

`[Ag(NH_(4))_(2)]Cl`

C

`[Ag(NH_(3))_(2)]OH`

D

`[Ag(NH_(3))_(2)]Cl`

Text Solution

Verified by Experts

The correct Answer is:
D
`AgCl+NH_(3) rarr underset("Diammine silver (I) chloride")([Ag(NH_(3))_(2)]Cl)`
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Knowledge Check

  • Silver chloride is soluble in methylamine due to the formation of :

    A
    `[Ag(CH_(3)NH_(2))_(4)]Cl`
    B
    `[Ag(CH_(3)NH_(2))_(2)]Cl`
    C
    `[Ag(CH_(3)NH_(2))_(3)]Cl`
    D
    `[Ag(CH_(3)NH_(2))]Cl`

  • Silver chloride is soluble in methylamine due to the formation of:

    A
    `[Ag(CH_(3)NH_(2)]Cl`
    B
    `[Ag(CH_(3)NH_(2))_(2)]Cl`
    C
    `[Ag(CH_(3)NH_(2))_(3)]Cl`
    D
    `[Ag(CH_(3)NH_(2))]Cl`

  • Zn^(+2) dissolves in excess of NaOH due to the formation of

    A
    Soluble `Zn(OH)_(2)`
    B
    Soluble `Na_(2)[Zn (OH)_(4)]`
    C
    Soluble `Na [Zn (OH)_(3)]`
    D
    `ZnO`

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    Silver chloride dissolves in excess of NH_4OH . The cation present in solution is.

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