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In the ground state of the hydrogen atom...

In the ground state of the hydrogen atom, the electron has a total energy of -13.6 eV. What are (a) its kinetic energy and (b) its potential energy if the electron is one Bohr radius from the central nucleus?

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To solve the problem, we need to find the kinetic energy (KE) and potential energy (PE) of the electron in the ground state of the hydrogen atom, given that the total energy (E) is -13.6 eV. ### Step-by-Step Solution: 1. **Understanding Total Energy**: The total energy (E) of the electron in the ground state of the hydrogen atom is given as: \[ E = -13.6 \, \text{eV} ...
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The ground state energy of hydrogen atom is-13.6 eV. What are the kinetic and potential energies of the electron in this state?

The ground state energy of hydrogen atom is -13.6 eV. What are the kinetic and potential energies of the electron in this state ?

Knowledge Check

  • The ratio of kinetic energy to the total energy of an electron in a Bohr orbit of the hydrogen atom, is

    A
    `1:-2`
    B
    `1:1`
    C
    `2:-1`
    D
    `1:-1`
  • The total energy of an electron in the second excited state of the hydrogen atom is about -1.5 eV. The kinetic energy and potential energy of the electron in this state are:

    A
    1.5 eV and -3 eV
    B
    `-1.5eV` and -1.5eV
    C
    3eV and -4.5 eV
    D
    `-0.75` eV and `-0.75eV`
  • A ground state hydrogen atom has an energy of -13.6 eV. If the electron is excited to the energy state n=3 , its energy ebcomes

    A
    `-12.09` eV
    B
    `-13.6` eV
    C
    `-4.5` eV
    D
    `-1.51` eV
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    The energy of the electron in the ground state of hydrogen atom is -13.6 eV . Find the kinetic energy and potential energy of electron in this state.

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