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If asintheta+bcostheta=c then prove that...

If `asintheta+bcostheta=c` then prove that `acostheta-bsintheta=sqrt(a^2+b^2-c^2)`

Answer

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Knowledge Check

  • If asintheta+bcostheta=c , then acostheta-b sintheta is equal to

    A
    `+-sqrt(a+b+c)`
    B
    `+-sqrt(a^(2)+b^(2)+c^(2))`
    C
    `+-sqrt(c^(2)+a^(2)-b^(2))`
    D
    `+-sqrt(c^(2)+a^(2)-b^(2))`

  • If asintheta+bcostheta=c , find acostheta-bsintheta=?

    A
    `pmsqrt(a^(2)+b^(2)+c^(2))`
    B
    `pmsqrt(a^(2)-b^(2)+c^(2))`
    C
    `pmsqrt(a^(2)+b^(2)-c^(2))`
    D
    none of these

    • Similar Questions

    Explore conceptually related problems

    If acostheta+bsintheta=c , then prove that: asintheta-bcostheta=+-sqrt(a^(2)+b^(2)-c^(2))

    If acostheta-bsintheta=c , then prove that: asintheta+bcostheta=+-sqrt(a^(2)+b^(2)-c^(2))

    If a cos theta-b sin theta=c; prove that a sin theta+b cos theta=+-sqrt(a^(2)+b^(2)-c^(2))

    If a cos theta - b sin theta =c , then prove that a sin theta + b cos theta = +- sqrt(a^(2) + b^(2) - c^(2))

    If a cos theta - b sin theta = c, prove that a sin theta + b cos theta = pm sqrt(a^(2) + b^(2) - c^(2)) .

    Evaluate (a+bcostheta)^2+(bsintheta)^2

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