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If x = log(a) bc, y = log(b) ca, z = log...

If x =` log_(a) bc, y = log_(b) ca, z = log_(c)`ab, then the value of `(1)/(1 + x) + (1)/(1 + y) + (1)/(l + z)` will be

A

`x + y + z `

B

1

C

ab + bc + ca

D

abc

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The correct Answer is:
B
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