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Give the chemical test to distinguish be...

Give the chemical test to distinguish between
(a) Hexane (I), `MeCH=CHCl (II)`,
Propylchloride (III), and `CH_(2)=CHCH_(2)Cl (IV)`
(b) `(V) CH_(3)Cl`, (VI) CH_(3)Br,` and `(VII) CH_(3)I`

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a. (IV) is allyl chloride which reacts with `AgNO_(3)` in cold to give a white precipiate of `AgCl, (I)` does not have `(Cl)` group so no reaction.
(III) is `1^(@) RX` which reacts with `AgNO_(3)` in hot to give a white precipiate of `AgCl`, since `(II)` is less reactivbe than `(IV)`
(II) is vinyl chloride which is inert even when heated and does not give white precipitate with `AgNO_(3)`.
(I) can be distinugulashed from others by adding `Br_(2)` in `CCl_(4)` to each the red-brown colour of `Br_(2)` is not decolourised by `(I)` while in others (alkens) it dissapers.
b. `(V) CH_(3)Cl overset(Aq. NaOH)(rarr) CH_(3) OH + Cl overset(Ag NO_(3))(rarr) underset(NH_(3))underset("soluble in")underset("White ppt"..,)(AgCl)`
`(VI) CH_(3) Br underset(NaOH)overset(Aq.)(rarr) CH_(3)OH + Br^(@) overset(Ag NO_(3))(rarr) underset("in" NH_(3))underset("Partly sounle")underset("ppt"..:)underset("Pale yellow")(AgBr)`
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`CH_(3)CH_(2)CH_(2)Cl(I),CH_(3)CH_(2)-CHCl-CH_(3)(II)(CH_(3))_(2)CHCH_(2)Cl(III),(CH_(3))_(3)C-Cl(IV)`

Arrange the folliwing compounds in increasing order of `SN^(-2)` reactivity.
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III. `CH_(3)CH = CHCH_(2)CH_(2)Cl`
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III. `CH_(2) = CHBr`
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