Home
Class 12
PHYSICS
The density of ice is 0.92 g/cm^(3) and ...

The density of ice is 0.92 g/`cm^(3)` and the density of seawater is 1.03 g/`cm^3`. A large iceberg floats in Arctic waters. What fraction of the volume of the iceberg is exposed?

A

`0.080` %

B

`11` %

C

0.89

D

0.92

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the fraction of the volume of the iceberg that is exposed above the water, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Given Densities**: - Density of ice, \( \rho_{\text{ice}} = 0.92 \, \text{g/cm}^3 \) - Density of seawater, \( \rho_{\text{water}} = 1.03 \, \text{g/cm}^3 \) 2. **Understand the Concept of Buoyancy**: - An iceberg floats due to the buoyant force, which is equal to the weight of the water displaced by the submerged part of the iceberg. - The weight of the iceberg can be expressed as \( mg \), where \( m \) is the mass of the iceberg. 3. **Set Up the Equation for Buoyancy**: - The buoyant force is given by: \[ F_b = V_{\text{submerged}} \cdot \rho_{\text{water}} \cdot g \] - Where \( V_{\text{submerged}} \) is the volume of the iceberg submerged in water. 4. **Relate Mass and Volume**: - The mass of the iceberg can also be expressed in terms of its volume and density: \[ m = V_{\text{total}} \cdot \rho_{\text{ice}} \] - Where \( V_{\text{total}} \) is the total volume of the iceberg. 5. **Equate the Forces**: - Since the iceberg is floating, the weight of the iceberg equals the buoyant force: \[ V_{\text{total}} \cdot \rho_{\text{ice}} \cdot g = V_{\text{submerged}} \cdot \rho_{\text{water}} \cdot g \] - The \( g \) cancels out from both sides: \[ V_{\text{total}} \cdot \rho_{\text{ice}} = V_{\text{submerged}} \cdot \rho_{\text{water}} \] 6. **Express the Submerged Volume**: - Rearranging the equation gives: \[ \frac{V_{\text{submerged}}}{V_{\text{total}}} = \frac{\rho_{\text{ice}}}{\rho_{\text{water}}} \] 7. **Calculate the Fraction**: - Substitute the known densities: \[ \frac{V_{\text{submerged}}}{V_{\text{total}}} = \frac{0.92}{1.03} \] 8. **Calculate the Value**: - Performing the division: \[ \frac{0.92}{1.03} \approx 0.8932 \] - This means approximately 89.32% of the iceberg is submerged in water. 9. **Determine the Exposed Volume**: - The fraction of the iceberg that is exposed is: \[ \text{Exposed fraction} = 1 - \frac{V_{\text{submerged}}}{V_{\text{total}}} \approx 1 - 0.8932 \approx 0.1068 \] - Converting to percentage: \[ \text{Exposed percentage} \approx 10.68\% \] ### Final Answer: The fraction of the volume of the iceberg that is exposed is approximately **10.68%**.
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • FLUIDS

    RESNICK AND HALLIDAY|Exercise PRACTICE QUESTIONS (More than One Correct Choice Type )|10 Videos
  • FLUIDS

    RESNICK AND HALLIDAY|Exercise PRACTICE QUESTIONS (Linked Comprehension )|9 Videos
  • FLUIDS

    RESNICK AND HALLIDAY|Exercise PROBLEMS|68 Videos
  • ELECTROMAGNETIC WAVES

    RESNICK AND HALLIDAY|Exercise PRACTICE QUESTIONS (Integer Type)|3 Videos
  • FORCE AND MOTION - I

    RESNICK AND HALLIDAY|Exercise PRACTICE QUESTIONS (Integer Type)|3 Videos

Similar Questions

Explore conceptually related problems

The density of wood is 0.65 g//cm^(3) . The density in SI system is

The density of ice is 0.918 g"cm"^(-3) and that of water is 1.03 g"cm"^(-3). An iceberg floats with a portion of 224 m^(3) outside the surface of water. Find the total volume of the iceberg.

Knowledge Check

  • An iceberg is floating partly immersed in sea water, the density of sea water is 1.03 g cm^(-3) and that of ice is 0.92 g cm^(-3) . The fraction of the total volume of the iceberg above the level of sea water is

    A
    `8.1 %`
    B
    `11%`
    C
    `34%`
    D
    `0.8%`
  • The density of ice x cm^(-3) and that of water is y gcm^(-3) . What is the change in volume when mg of ice melts?

    A
    `m(y-x)cm^(3)`
    B
    `(y-x)/(m) cm^(3)`
    C
    `mxy(x-y)cm^(3)`
    D
    `m((1/y-1/x) cm^(3)`.
  • An iceberg is floating partly immersed in sea water, the density of sea water is 1.03 g and that of ice is 0.92 g . The fraction of the total volume of the iceberg above the level of sea water is

    A
    `8 . 1% `
    B
    `11 %`
    C
    `34%`
    D
    `0.9%`
  • Similar Questions

    Explore conceptually related problems

    The density of alcohol is 800kg//m^(3) . Then the density in g//cm^(3) is _______

    An iceberg is floating partially immersed in sea water the density of sea water is 1.03 gm//cm^(3) and that of ice is 0.92gm//cm^(3) what is the fraction of the total volume of the iceberg above the level of sea-water?

    If the density of iron is 7.85 g cm^(-3) and density of water is 1000 kg m-3, then the relative density of iron is __________.

    The volume of 50g of a substance is 20cm^(3) . If the density of water is 1g cm^(-3) , will the substance float or sink ?

    An iceberg is floating in water. The density of ice in the iceberg is 917 kg m^(-3) and the density of water is 1024 kg m^(-3) . What percentage fraction of the iceberg would be visible?