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Calculate emf of the following cell at 2...

Calculate emf of the following cell at 298 K :
`2Cr(s) + 2Fe^(2+)(0.1 M) to 2Cr^(3+) (0.01 M) + 3Fe(s)`
Given: `E_(Cr^(2+)//Cr)^(@) =-0.74 V, E_(Fe^(2+)//Fe)^(@) = -0.44 V`

Text Solution

Verified by Experts

The correct Answer is:
0.3098 V
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Calcualte the emf of the following cell at 298 K: 2Cr(s) + 3Fe^(2+) (0.1 M ) to 2Cr^(3+) (0.01 M) + 3Fe(s) Given: E_("Cr^(3+)//Cr)^(@) = -0.74 V, E_(Fe^(2+)//Fe)^(@) = -0.44 V .

Calculate e.m.f. of the following cell at 298 K, 2Cr(s)+3Fe^(2+)(0.1 M) to 2Cr^(3+)(0.01 M)+3Fe(s) ("Given" : E_((Cr^(3+)//Cr))^(@)=-0.74" V ", E_((Fe^(2+)//Fe))^(@)=-0.44" V ")

Knowledge Check

  • What will be standard cell potential of galvanic cell with the following reaction? 2Cr(s) + 3Cd^(2+)(aq) to 2Cr^(3+)(aq) + 3Cd(s) [Given: E_(Cr^(3+)//Cr)^(@) = -0.74 V and E_(Cu^(2+)//Cu)^(@) = -0.4 V

    A
    0.70V
    B
    1.14 V
    C
    0.34 V
    D
    `-0.34 V`

  • What will be standard cell potential of galvanic cell with the following reaction? 2Cr(s) + 3Cd^(2+)(aq) to 2Cr^(3+)(aq) + 3Cd(s) [Given: E_(Cr^(3+)//Cr)^(@) = -0.74 V and E_(Cu^(2+)//Cu)^(@) = -0.4 V

    A
    0.70V
    B
    1.14 V
    C
    0.34 V
    D
    `-0.34 V`

  • What is the value of E^(@) cell in the following reaction? Cr|Cr^(3+) (0.1 M)||Fe^(2+) (0.01 M)|Fe Given, E_(Cr^(3+)//Cr)^(@)=-0.74 V, E_(Fe^(2+)//Fe)^(@)=-0.44 V

    A
    `+ 0.2606 V`
    B
    `0.5212 V`
    C
    `+ 01303 V`
    D
    `-0.2606 V`

    • Similar Questions

    Explore conceptually related problems

    Calculate the e.m.f. of the following cell at 298K: 2Cr(s)+3Fe^(2+)(0.1M)to2Cr^(3+)(0.01M)+3Fe(s) Given: E_((Cr^(3+)//Cr))^(@)=-0.74V,E_((Fe^(2+)//Fe))^(@)=-0.44V .

    Calculate E_(cell)^(@) for the following reaction at 298 K : 2 Cr (s ) + 3 Fe^(2+) (0.01 M) to 2 Cr^(3+) (0.01 M) + 3 Fe (s) Given : E_(cell) = 0.261 V

    Calculate the emf of the following cell at 298 K: Cr(s)//Cr^(3+) (0.1 m)//Fe^(2+) (0.01 M)//Fe(s) [Given: E_("cell")^(@) = +0.30 V ]

    Calculate the e.m.f. of the cell, Cr//Cr^(3+)(0.1 M) || Fe^(2+)(0.01 M)//Fe "Given" : E_(Cr^(3+)//Cr)^(@)=-0.75" V ", E_(Fe^(2+)//Fe)^(@)=-0.45" V " "Cell reaction" : 2Cr(s)+3Fe^(2+)(aq) to 2Cr^(3+)(aq)+3Fe(s) {"Hint". E_(cell)=E_(cell)^(@)-(0.0591V)/(6)"log"([Cr^(3+)]^(2))/([Fe^(2+)]^(3)}

    Calculate the emf of the cell Cr|Cr^(3+) (0.1 M) ||Fe^(2+) (0.01 M)|Fe ("Given: "E_(Cr^(3+)//Cr)^(@)=- 0.75" volt, "E_(Fe^(2+)//Fe)^(@)=-0.45" volt")

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