Calculate the lattice enthalpy of `CaCl_(2)` given that the enthalpy of : i) Sublimation of Ca in `"121.8 kJ mol"^(-1)` ii) Dissociation of `Cl_(2)` to `2Cl` is `"242.8 kJ mol"^(-1)` iii) Ionisation of `Ca" to "Ca^(2+)" is 2422 kJ mol"^(-1)` iv) Electron gain for `Cl" to "Cl^(-)" is - 355 kJ mol"^(-1)` v) `DeltaH_(f)^((o))" overall is "-"795 kJ mol"^(-1)`
Topper's Solved these Questions
CHEMICAL BONDING
NCERT GUJARATI|Exercise Questions(E. Explain briefly on the following)|1 Videos
BASIC CONCEPTS OF ORGANIC CHEMISTRY
NCERT GUJARATI|Exercise Questions|11 Videos
CHEMICAL CALCULATION
NCERT GUJARATI|Exercise Question ( Answer the following )|7 Videos
Similar Questions
Explore conceptually related problems
Calculate the enthalpy of combustion of ethylene at 300K at constant pressure if its enthalpy of combustion at constant volume is -"1406 kJ mol"^(-1) .
Heat of neutralisation of a weak acid HA by NaOH is -"12.13 kJ mol"^(-1) . Calculate the enthalpy of ionization of HA. The Heat of neutralisation of a strong acid with strong base is -"54.9 kJ mol"^(-1)
NCERT GUJARATI-CHEMICAL BONDING-Questions(E. Explain briefly on the following)