Home
Class 12
CHEMISTRY
The formation of water from H(2(g)) and ...

The formation of water from `H_(2(g)) and O_(2(g))` is an exothermic reaction because

A

`H_(2(g)) and O_(2(g))` have a higher chemical energy that water

B

`H_(2(g)) and O_(2(g))` have a lower chemical energy that water

C

`H_(2(g)) and O_(2(g))` have higher temperature than water

D

Energy considerations do not arise

Text Solution

Verified by Experts

The correct Answer is:
A
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • CHEMICAL THERMODYNAMICS

    AAKASH SERIES|Exercise Lecture Sheet Exercise-III|23 Videos
  • CHEMICAL THERMODYNAMICS

    AAKASH SERIES|Exercise Lecture Sheet -Exercise-IV|16 Videos
  • CHEMICAL THERMODYNAMICS

    AAKASH SERIES|Exercise Additional Practice Exercise|54 Videos
  • CHEMICAL KINETICS

    AAKASH SERIES|Exercise Objective Exercise - 4 (Assertion (A) & Reason (R) Type Questions)|44 Videos
  • CHEMISTRY IN EVERY DAY LIFE

    AAKASH SERIES|Exercise PRACTICE EXERCISE|29 Videos

Similar Questions

Explore conceptually related problems

The concentration of 2NO_(2)(g)hArrN_(2)O_(4)(g) is an exothermic equilibrioum . This means that:

Write the equations for the conversion of K_(c) to K_(p) for each of the following reactions. C_(3)H_(8)(g)+5O_(2)(g) 3CO_(2)(g)+4H_(2)O(g)

Knowledge Check

  • From the following data at 25^(@)C {:("Reaction",Delta_(r)H^(@) kJ//mol),((1)/(2)H_(2(g)) + (1)/(2)O_(2(g)) rarr OH_((g)),42),(H_(2(g)) + (1)/(2) O_(2(g)) rarr H_(2)O_((g)),-242),(H_(2(g)) rarr 2H_((g)),436),(O_(2(g)) rarr 2O_((g)),495):} which of the following statement(s) is/are correct Statement (a): Delta_(r)H^(@) for the reaction H_(2)O_((g)) rarr 2H_((g)) + O_((g)) is 925.5 kJ/mol Statement (b): Delta_(r) H^(@) for the reaction OH_((g)) rarr H_((g)) + O_((g)) is 502 kJ/mol Statement (c ): Enthalpy of formation of H_((g)) " is " -218 kJ/mol Statement (d): Enthalpy of formation of OH_((g)) is 42 kJ/mol

    A
    Statement c
    B
    Statement a, b, c
    C
    Statement b, c
    D
    statement a,d
  • The formation of the oxide ion O _((g)) ^(2-) from oxygen atom requires first an exothermic and then an endothermic step as shown below : O _((g)) + e ^(-) to O _((g )) ^(-) ,Delta _(f) H^(0) =-141 kJ mol ^(-1) O _((g)) ^(-) +e ^(-) to O _((g)) ^(-2) ,Delta _(f) H^(0) =+ 780 kJ mol ^(-1) Thus, process of formation of O^(2-) in gas phase is unfavourable even thrugh O ^(2-) is isoelectronic with neon. It is due to the fact that (2015)

    A
    `O^(-)` ion has comparatively smaller size than oxygen atom
    B
    Oxygen is more electronegative
    C
    Addition of electron in oxygen result in larger size of the ion
    D
    Electron repulsion outweights the stability gained by achieving noble gas configuration.
  • The enthalpy of formation of N_2O_((g)) and NO_((g)) are 82.0 KJ and 90 KJmol^(-1) respectively. The enthalpy of the reaction 2N_2O_((g)) + O_(2(g)) rarr 4NO_((g)) is

    A
    `80 KJ`
    B
    `88.0KJ`
    C
    `-16.0KJ`
    D
    `196.0 K`
  • Similar Questions

    Explore conceptually related problems

    Which of the indicated relationship is correct for the following exothermic reaction carried out at constant pressure? CO_((g)) + 3H_(2(g)) rarr CH_(4(g)) + H_(2)O_((g))

    The enthalpy of the reaction H_(2(g)) + O_(2(g)) rarr H_2O_((g)) is DeltaH_1 and that of H_(2(g)) + O_(2(g)) rarr H_(2)O_((l)) is Delta H_2 . Then

    Assertion (A): The enthalpy of formation of H_(2)O_((l)) is greater than that of H_(2)O_((g)) Reason (R ): Enthalpy change is negative for the condensation reaction H_(2)O_((g)) rarr H_(2)O_((l))

    Standard Enthalpy (Heat) of formation of liquid water at 25^@C is around H_2(g) + 1/2 O_2(g) rightarrow H_2O_(l).

    At T(K), the ratio of kinetic energies of 4g of H_(2) (g) and 8g of O_(2) (g) is