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For a reaction R(1), Delta G = x KJ mol^...

For a reaction `R_(1), Delta G = x KJ mol^(-1)`. For a reaction `R_(2), Delta G = y KJ mol^(-1)`. Reaction `R_(1)` is non-spontaneous but along with `R_(2)` it is spontaneous. This means that

A

x is -ve, y is +ve but in magnitude `x gt y`

B

x is +ve, y is -ve but in magnitude `y gt x`

C

Both x and y are -ve but not equal

D

Both x and y +ve but not equal

Text Solution

Verified by Experts

The correct Answer is:
B
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