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A cell of emf 'E' and internal resistanc...

A cell of emf 'E' and internal resistance 'r' draws a current 'I'. Write the relation between terminal voltage 'V' in terms of E, I and r.

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AI Generated Solution

To find the relation between the terminal voltage \( V \), the electromotive force (emf) \( E \), the current \( I \), and the internal resistance \( r \) of a cell, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Definitions**: - The **emf** \( E \) of a cell is the maximum potential difference when no current is flowing. - The **terminal voltage** \( V \) is the potential difference across the terminals of the cell when current is flowing. ...
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A cell of emf ‘E’ and internal resistance ‘r’ is connected across a variable load resistor R. Draw the terminal voltage V versus (i) R and (ii) the current l. It is found that when R=4 Omega , the current is 1 A and when R is increased to 9 Omega , the current reduct Find the values of the emf E and internal resistance r.

A cell of emf epsi and internal resistance 'r' is connected across a variable load resistor 'R'. Draw the plots of the terminal voltage 'V' versus (i) R and (ii) the current I. It is found that when R = 4 Omega , the current is 1 A and when R is increased to 9 Omega , the current reduces to 0.5 A. Find the values of the emf epsi and internal resistance r.

Knowledge Check

  • A cell of emf epsilon and internal resistance r is charged by a current I, then

    A
    the cell stores chemical energy at the rate of `epsiloni`
    B
    the cell stores chemical energy at the rate of `i^2r`
    C
    the cell stores chemical energy at the rate of `epsilon I - i^2r `
    D
    the storage of chemical energy rate cannot be calculated

  • A cell of emf 'E' and internal resistance 'r' is connected to a variable external resistor 'R'. The graph which gives the terminal voltage of cell 'V' with respect to R is :

    A
    B
    C
    D

  • A cell of emf E and internal resistance r is connected in series with an external resistance nr. Then, the ratio of the terminal potential difference to emf is :

    A
    `((1)/(n))`
    B
    `(1)/((n+1))`
    C
    `(n)/((n+1))`
    D
    `((n+1))/(n)`

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