Home
Class 12
PHYSICS
A 5 V battery of negligible internal re...

A 5 V battery of negligible internal resistance is connected across a 200 V battery and a resistance of `39 Omega` as shown in the figure. Find the value of the current.

Text Solution

Verified by Experts

Value of current, `i=(200-5)/(39) = 5A.`
Promotional Banner

Topper's Solved these Questions

  • XII BOARDS

    XII BOARDS PREVIOUS YEAR|Exercise [SET - I]|32 Videos
  • XII BOARDS

    XII BOARDS PREVIOUS YEAR|Exercise [SET - II DELHI BOARD]|6 Videos
  • XII BOARDS

    XII BOARDS PREVIOUS YEAR|Exercise SET - II (Delhi Board)|8 Videos
  • SAMPLE PAPER 2019

    XII BOARDS PREVIOUS YEAR|Exercise SECTION D|6 Videos

Similar Questions

Explore conceptually related problems

A 10 V battery of negilgible internal resistance is connected across a 200V battery and a resistance of 38 Oemga as shown in figure. . Find the value of current in the circuit.

A 10 V cell of neglible internal resitsance is connected in parallel across a battery of emf 200 V and internal resistance 38 Omega as shown in the figure. Find the value of current in the circuit.

A battery of emf 2V and internal resistance 0.5(Omega) is connected across a resistance in 1 second?

A potentiometer wire has length 10 m and resistance 20Omega . A 2. 5 V battery of negligible internal resistance is connected across the wire with an 80 Omega series resistance. The potential gradient on the wire will be

A 5 V battery with internal resistance 2Omega and a 2V battery with internal resistance 1Omega are connected to a 10Omega as shown in the figure. The current in the 10Omega resistance is

A 5V battery with internal resistance 2Omega and a 2V battery with internal resistance 1Omega are connected to a 10Omega resistor as shown in the figure. The current in the 10Omega resistor is

Five 4 Omega resistance, 2 V battery and an ammeter are connected as shown in figure. Find the ammeter reading.