Home
Class 11
MATHS
Find the equation of the set of points w...

Find the equation of the set of points which are equidistant from the points `(1, 2, 3)`and `(3, 2, 1)`.

Text Solution

AI Generated Solution

To find the equation of the set of points that are equidistant from the points \( A(1, 2, 3) \) and \( B(3, 2, 1) \), we can follow these steps: ### Step 1: Define the points and the point \( P \) Let the point \( P \) have coordinates \( (x, y, z) \). The points \( A \) and \( B \) are given as: - \( A(1, 2, 3) \) - \( B(3, 2, 1) \) ### Step 2: Set up the distance equations ...
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • INTRODUCTION TO THREE DIMENSIONAL GEOMETRY

    NCERT ENGLISH|Exercise EXERCISE 12.3|5 Videos
  • INTRODUCTION TO THREE DIMENSIONAL GEOMETRY

    NCERT ENGLISH|Exercise EXERCISE 12.1|4 Videos
  • INTRODUCTION TO THREE DIMENSIONAL GEOMETRY

    NCERT ENGLISH|Exercise MISCELLANEOUS EXERCISE|6 Videos
  • CONIC SECTIONS

    NCERT ENGLISH|Exercise EXERCISE 11.1|15 Videos
  • LIMITS AND DERIVATIVES

    NCERT ENGLISH|Exercise EXERCISE 13.3|8 Videos

Similar Questions

Explore conceptually related problems

Find the locus of the points which are equidistant from the points (1,2,3) and (3,2,11).

Find the equation of the set of all points which are equidistant from the points (a^2 + b^2 , a^2 - b^2) and (a^2 - b^2 , a^2 + b^2)

Knowledge Check

  • The locus of the point which is equidistant from the point A(0, 2, 3) and B(2, -2, 1) is

    A
    x - 2y - z + 1 = 0
    B
    x + 2y - z - 1 = 0
    C
    x + 2y + z + 1 = 0
    D
    None of these
  • Similar Questions

    Explore conceptually related problems

    Find the equation to the locus of points equidistant from the points (-3,2),(0,4)

    The equation of the set of all points which are equidistant from the point (0, 4) and the line y = -4

    Find the equation of the set of all points equidistant form the point (4, 2) and the X-axis.

    Determined the equation to the locus of the point which is equidistant from the points ( 2 , - 2 , - 4) and ( - 3 , 1 , 2) .

    Derive the equation of the locur of a point equidistant from the points (1, -2, 3) and (-3,4,2).

    Find the equation to the locus of a point equidistant from the points A(1,3)a n dB(-2,1)dot

    Find the locus of the point which is equidistant from the points A(0,2,3) and B(2,-2,1)dot