A steel wire of length `4.7 m` and cross-sectional area `3 xx 10^(-6) m^(2)` stretches by the same amount as a copper wire of length `3.5 m` and cross-sectional area of `4 xx 10^(-6) m^(2)` under a given load. The ratio of Young's modulus of steel to that of copper is

Explanation

To find the ratio of Young's modulus of steel to that of copper, we will use the formula for Young's modulus, which is defined as:

\[ Y = \frac{\text{Stress}}{\text{Strain}} = \frac{F/A}{\Delta L/L} \]

Where:
- \(Y\) is Young's modulus
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