Given the hybridistaiton state of each carbon in the following compounds :
I. `CH_(2) = C = O` II. `CH_(3) - CH = CH_(2)`
III. `(CH_(3))_(2) CO` IV. `CH_(2) = CH = C -= N`
v. `C_(6) H_(6)`

Explanation

To determine the hybridization state of each carbon in the given compounds, we will analyze each compound step by step. The hybridization can be determined by calculating the steric number, which is the sum of the number of sigma bonds and lone pairs around the carbon atom.

### Step-by-Step Solution:

**I. `CH₂=C=O`**
1. For the first carbon (C1):
- It forms 2 sigma bonds with hydrogen atoms and 1 sigma bond with the second carbon (C2).
- Total sigma bonds = 2 (H) + 1 (C2) = 3
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