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(a) Define the following terms: (i) Li...

(a) Define the following terms:
(i) Limiting molar conductivity
(ii) Fuel cell.
(b) Resistance of a conductivity cell filled with 0.1 `mol L^-1 KCl` solution is `100 Omega`. IF the resistance of the same cell when filled with `0.02 mol L^-1 KCl` solution is `520 Omega`, calculate the conductivity and molar conductivity of `0.02 mol L^-1 KCl` solution. The conductivity of `0.1 mol L^-1` KCl solution is `1.29 times 10^-2 Omega^-1 cm^-1`.

Text Solution

Verified by Experts

(a) (i) Limiting molar conductivity: When concentration approaches zero the conductivity is known as limiting molar conducitivity.
(ii) Fuel cell: A fuel cells which convert the energy of combustion of fuels to electrical energy.(b) Given, cell constant =`G^@`
`= conductivity times Resistance `
`thereforeG^@=1.29S//m times 100 Omega`
`=129 m^-1=1.29 cm^-1`
Conductivity of `0.02 mol L^-1`, KCl solution = cell constant/resistance
`K=G^*/R=(129 m^-1)/(520 Omega)=0.248 S m^-1`
`=0.248 times 10^-2 Scm^-1`
Concentration =`0.02 mol L^-1`
`=1000 times 0.2 mol m^-3`
`=20 mol m^-3`
Molar conductivity =`A_m=K/C`
`=(248 times 10^-3 Sm^-1)/(20 mol m^-3)`
`=124 times 10^-4 S m^2 mol^-1`
`=124 S cm^2 mol^-1`
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Resistance ofa conductivity cell filled with 0.1 mol L^(-1) KCl solution is 100Omega . If the resistance of the same cell when filled with 0.02 molL^(-1) KCl solution is 520 Omega . Calculate the conductivity and molar conductivity of 0.02 mol L^(-1) KCl solution. The conductivity of 0.1 mol L^(-1) KCl solution is 1.29 S//m .

The resistance of a conductivity cell filled with 0.1 M KCl solution is 100 Omega . If R of the same cell when filled with 0.02 M KCl solution is 520 Omega , calculate the conductivity and molar conductivity of 0.02 M KCl solution. The conductivity of 0.1 M KCl solution is 1.29 S m^(-1) .

Knowledge Check

  • Resistance of conductivity cell filled with a solution on an electrolyte of concentration 0.1 M is 100 Omega . The conductivity of this solution is 1.29 S m^(-1) . Resistance of the same cell when filled with 0.2 M of the same solution is 520Omega . The molar conductivity of 0.02 M solution of the electrolyte will be

    A
    `1240 xx 10^(-4) S m^2 mol^(-1)`
    B
    `1.24 xx 10^(-4) S m^2 mol^(-1)`
    C
    `12.4 xx 10^(-4) S m^2 mol^(-1)`
    D
    `124 xx 10^(-4) S m^2 mol^(-1)`

  • Resistance of a conductivity cell filled with a solution of an electrolyte of concentration 0.1M is 100 Omega. The conductivity of this solution is 1.29S m ^(-1). Resistance of the same cell when filled with 0.2M of the same solution is 520 Omega. The molar conductivity of 0.2M solution of the electrolyte will be

    A
    `1240xx 10 ^(-4) S m 6(2) mol ^(-1)`
    B
    `1. 24 xx 10 ^(-4) S m^(2) mol ^(-1)`
    C
    `12.4 xx 10 ^(-4) S m ^(2) mol ^(-1)`
    D
    `124 xx 10 ^(-4) S m ^(2) mol ^(-1)`

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    Define the following terms: (i) Fuel cell (ii) Limiting molar conductivity

    Define limiting molar conductivity?

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    Express the relation between the conductivity and the molar conductivity of a solution.

    c) Resistance of a conductivity cell containing 0.1 M KCl solution is 100Omega . Cell constant of the cell is 1.29/cm. Calculate the conductivity of the solution at the same temperature.

    The resistance of a conductivity cell containing 0.001 M KCl solution at 298 K is 1500 Omega . What is the cell constant if conductivity of 0.001 M KCl solution at 298 K is 0.146 X 10^(-3) Scm^(-1) ?

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